题目
题型:不详难度:来源:
![](http://img.shitiku.com.cn/uploads/allimg/20191103/20191103100504-23668.png)
(1)求
![](http://img.shitiku.com.cn/uploads/allimg/20191103/20191103100504-72422.png)
(2)求
![](http://img.shitiku.com.cn/uploads/allimg/20191103/20191103100504-32245.png)
答案
![](http://img.shitiku.com.cn/uploads/allimg/20191103/20191103100505-96132.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191103/20191103100505-76105.png)
(2)
![](http://img.shitiku.com.cn/uploads/allimg/20191103/20191103100505-98076.png)
解析
解:(1)因为
![](http://img.shitiku.com.cn/uploads/allimg/20191103/20191103100504-23668.png)
所以
![](http://img.shitiku.com.cn/uploads/allimg/20191103/20191103100505-96132.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191103/20191103100505-96201.png)
(2)
![](http://img.shitiku.com.cn/uploads/allimg/20191103/20191103100505-98076.png)
核心考点
举一反三
![](http://img.shitiku.com.cn/uploads/allimg/20191103/20191103100457-11775.png)
A.![]() | B.![]() |
C.![]() | D.![]() |
A.若两个向量相等,则它们的起点和终点分别重合. |
B.模相等的两个平行向量是相等向量. |
C.若![]() ![]() ![]() |
D.两个相等向量的模相等. |
![](http://img.shitiku.com.cn/uploads/allimg/20191103/20191103100449-93125.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191103/20191103100449-61177.png)
A.![]() | B.![]() | C.![]() | D.![]() |
![](http://img.shitiku.com.cn/uploads/allimg/20191103/20191103100441-90029.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191103/20191103100442-40008.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191103/20191103100442-46423.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191103/20191103100442-77145.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191103/20191103100443-27139.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191103/20191103100441-90029.png)
A.![]() | B.![]() | C.![]() | D.![]() |
A.![]() | B.![]() |
C.![]() | D.![]() |
A.若两个向量相等,则它们的起点和终点分别重合. |
B.模相等的两个平行向量是相等向量. |
C.若![]() ![]() ![]() |
D.两个相等向量的模相等. |
A.![]() | B.![]() | C.![]() | D.![]() |
A.![]() | B.![]() | C.![]() | D.![]() |