题目
题型:不详难度:来源:
2 |
9 |
4 |
答案
y2 |
a2 |
x2 |
b2 |
∵双曲线过点P1(3,-4
2 |
9 |
4 |
∴
|
∴b2=9,a2=16
∴双曲线方程为:
y2 |
16 |
x2 |
9 |
故答案为:
y2 |
16 |
x2 |
9 |
核心考点
举一反三
x2 |
a2 |
y2 |
b2 |
3 |
(1)求双曲线的方程;
(2)任作一直线l与双曲线右支交于两点A,B,与渐近线交于两点C,D,A在B,C两点之间,求证:|AC|=|BD|.
x2 |
16 |
y2 |
4 |
2 |
1 |
2 |
1 |
4 |
2 |
9 |
4 |
y2 |
a2 |
x2 |
b2 |
2 |
9 |
4 |
|
y2 |
16 |
x2 |
9 |
y2 |
16 |
x2 |
9 |
x2 |
a2 |
y2 |
b2 |
3 |
x2 |
16 |
y2 |
4 |
2 |
1 |
2 |
1 |
4 |