题目
题型:解答题难度:一般来源:宜宾模拟
x+2 |
x-5 |
(1)求集合S;
(2)若S⊆P,求实数a的取值范围.
答案
x+2 |
x-5 |
解得-2<x<5,(4分)
则集合S={x|-2<x<5}.(6分)
(II)因为S⊆P,所以
|
解得
|
所以a∈[-5,-3].(12分)
核心考点
举一反三
A.M=P | B.P∈M | C.M⊊P | D.P⊊M |
2 |
2 |
1 |
2n |
1 |
4n |
A.M∩P=∅ | B.(CUM)∩P=∅ | C.M∩(CUP)=∅ | D.(CUM)∩(CUP)=∅ |
x+2 |
x-5 |
x+2 |
x-5 |
|
|
A.M=P | B.P∈M | C.M⊊P | D.P⊊M |
2 |
2 |
1 |
2n |
1 |
4n |
A.M∩P=∅ | B.(CUM)∩P=∅ | C.M∩(CUP)=∅ | D.(CUM)∩(CUP)=∅ |