题目
题型:解答题难度:一般来源:不详
1 |
ab |
1 |
(a+1)(b+1) |
1 |
(a+2)(b+2) |
1 |
(a+2007)(b+2007) |
答案
所以ab-2=0,b-1=0,
所以b=1,a=2,
所以原式=
1 |
1×2 |
1 |
2×3 |
1 |
3×4 |
1 |
2008×2009 |
=1-
1 |
2 |
1 |
2 |
1 |
3 |
1 |
3 |
1 |
4 |
1 |
2008 |
1 |
2009 |
1 |
2009 |
2008 |
2009 |
核心考点
举一反三
1 |
ab |
1 |
(a+1)(b+1) |
1 |
(a+2)(b+2) |
1 |
(a+2007)(b+2007) |
1 |
1×2 |
1 |
2×3 |
1 |
3×4 |
1 |
2008×2009 |
1 |
2 |
1 |
2 |
1 |
3 |
1 |
3 |
1 |
4 |
1 |
2008 |
1 |
2009 |
1 |
2009 |
2008 |
2009 |