题目
题型:不详难度:来源:
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032733-99149.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032733-78428.png)
(1)求C的圆心轨迹L的方程;
(2)设直线l是圆O:
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032733-81287.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032733-50977.png)
答案
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032734-10130.png)
解析
试题分析:(1)设两圆的圆心分别为F1、F2,圆C的半径为r
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032734-31599.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032734-70247.png)
或
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032734-47844.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032734-67395.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032735-84650.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032735-84650.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032734-10130.png)
(2)由题可得直线l的方程为
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032735-18643.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032735-46192.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032735-82146.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032736-30412.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032736-17292.png)
点评:此类轨迹方程的求法利用了定义法,所谓定义法就是立足题中所给的条件,结合题意导出相应的关系式,之后再根据特殊曲线的定义得出曲线的方程
核心考点
试题【设圆C与两圆,中的一个内切,另一个外切.(1)求C的圆心轨迹L的方程;(2)设直线l是圆O:在P(x0,y0)(x0y0 ≠ 0)处的切线,且P在圆上,l与轨迹】;主要考察你对双曲线的定义与方程等知识点的理解。[详细]
举一反三
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032724-58304.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032724-32732.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032725-85173.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032725-78757.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032725-26277.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032725-70040.png)
A.![]() | B.![]() | C.![]() | D.![]() |
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032720-58028.png)
A.![]() | B.![]() | C.2 | D.![]() |
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032715-12320.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032715-10160.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032715-58321.png)
A.![]() | B.![]() | C.![]() | D.![]() |
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032708-62039.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032708-13663.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032708-86838.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032708-62039.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032709-53785.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032709-58850.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032709-40201.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032709-78237.png)
A.![]() | B.![]() | C.![]() | D.![]() |
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032703-65109.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032703-74153.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032703-26602.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032703-26602.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032703-68599.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032704-91442.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032704-95284.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032704-95555.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191024/20191024032704-95388.png)
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