题目
题型:不详难度:来源:
![](http://img.shitiku.com.cn/uploads/allimg/20191108/20191108003146-43228.jpg)
①∠B=∠ACD;
②∠ADC=∠ACB;
③
![](http://img.shitiku.com.cn/uploads/allimg/20191108/20191108003146-40661.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191108/20191108003146-28495.png)
④AC2=AD·AB.
其中能够单独判定△ABC∽△ACD的个数为
A.1 B.2 C.3 D.4
答案
解析
题号 | 判断 | 原因分析 |
① | √ | ∵∠B=∠ACD,又∠A=∠A,∴由判定定理1,知△ABC∽△ACD |
② | √ | ∵∠ADC=∠ACB,又∠A=∠A,∴由判定定理1,知△ABC∽△ACD |
③ | × | ∵![]() ![]() ![]() ![]() |
④ | √ | ∵AC2=AD·AB,∴![]() ![]() |
核心考点
试题【如图所示,给出下列条件: ①∠B=∠ACD;②∠ADC=∠ACB;③=;④AC2=AD·AB.其中能够单独判定△ABC∽△ACD的个数为A.1 B.2 C.】;主要考察你对圆锥曲线性质探讨等知识点的理解。[详细]
举一反三
![](http://img.shitiku.com.cn/uploads/allimg/20191108/20191108003140-78308.jpg)
①△AOB∽△COD;
②△AOD∽△ACB;
③S△DOC∶S△AOD=CD∶AB;
④S△AOD=S△BOC.
其中正确的个数为( ).
A.1 | B.2 | C.3 | D.4 |
![](http://img.shitiku.com.cn/uploads/allimg/20191108/20191108003136-57811.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191108/20191108003137-76429.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191108/20191108003137-94093.png)