题目
题型:不详难度:来源:
a |
b |
a |
b |
a |
b |
a |
a |
b |
答案
a |
a |
b |
a |
a |
b |
a |
1 |
2 |
故答案为:
1 |
2 |
核心考点
试题【若向量a,b满足|a|=|b|=1,a与b的夹角为120°,则a•(a+b)=______.】;主要考察你对平面向量数量积的运算等知识点的理解。[详细]
举一反三
9 |
2 |
3 |
2 |
(1)求点P的轨迹方程;
(2)若F′(-2,0),求
PF |
PF′ |
a |
3θ |
2 |
3θ |
2 |
b |
θ |
2 |
θ |
2 |
π |
3 |
(1)求
| ||||
|
|
(2)若|k
a |
b |
3 |
a |
b |
(1)若点A(1,
π |
2 |
AP |
(2)若直线l的参数方程是
|
CM |
CN |
(Ⅰ)若线段AB中点的横坐标是-
1 |
2 |
(Ⅱ)设点M的坐标为(-
7 |
3 |
MA |
MB |