当前位置:高中试题 > 数学试题 > 平面向量的加法 > 设O是直线AB外一点,OA=a,OB=b,点A1,A2,A3…An-1是线段AB的n,(n≥2)等分点,则OA1+OA2+OA3+…+OAn-1=______(...
题目
题型:卢湾区一模难度:来源:
设O是直线AB外一点,


OA
=


a


OB
=


b
,点A1,A2,A3…An-1是线段AB的n,(n≥2)等分点,则


OA1
+


OA2
+


OA3
+…+


OAn-1
=______(用


a


b
,n表示).
答案
由题意可得


OA1
=


OA
+


AA1
=


OA
+
1
n


AB
=


OA
+
1
n
(


OB
-


OA
)=


a
+
1
n
(


b
-


a
)



OA2
=


OA


+AA2
=


OA
+
2
n


AB
=


OA
+
2
n
(


OB
-


OA
)=


a
+
2
n
(


b
-


a
)




OAn-1
=


OA


+AAn-1
=


OA
+
n-1
n


AB
=


OA
+
n-1
n
(


OB
-


OA
)=


a
+
n-1
n
(


b
-


a
)

把以上n-1个式子相加得


OA1
+


OA2
+


OA3
+…+


OAn-1
=(n-1)


a
+
1+2+3+…+(n-1)
n
(


b
-


a
)

=(n-1)


a
+
n(n-1)
2n
(


b
-


a
)
=
n-1
2
(


a
+


b
)

故答案为
n-1
2
(


a
+


b
)
核心考点
试题【设O是直线AB外一点,OA=a,OB=b,点A1,A2,A3…An-1是线段AB的n,(n≥2)等分点,则OA1+OA2+OA3+…+OAn-1=______(】;主要考察你对平面向量的加法等知识点的理解。[详细]
举一反三
设A1,A2,A3,A4 是平面上给定的4个不同点,则使


MA1
+


MA2
+


MA3
+


MA4
=


0
 成立的点M 的个数为(  )
A.0B.1C.2D.4
题型:上海难度:| 查看答案
P是△ABC所在平面内一点,且满足


PB
+


PC
=2


AB
,已知△ABC的面积是1,则△PAB的面积是______.
题型:重庆三模难度:| 查看答案
设A1,A2,A3,A4,A5是平面上给定的5个不同点,则使


MA1
+


MA2
+


MA3
+


MA4
+


MA5
=


0
成立的点M的个数为(  )
A.0B.1C.5D.10
题型:上海难度:| 查看答案


a
=(1,2)


b
=(-3,4)
,则
1
12
[2(2


a
-8


b
)-4(4


a
+2


b
)]
=(  )
A.(5,0)B.(5,-10)C.(4,-2)D.(-4,2)
题型:不详难度:| 查看答案
在四边形ABCD中,


AB
=(1,2),


BC
=(-4,-1),


CD
=(-5,-3),则四边形ABCD是(  )
A.长方形B.梯形C.平行四边形D.以上都不对
题型:不详难度:| 查看答案
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