题目
题型:不详难度:来源:
(1)求X<2且Y>1时的概率
(2)某人玩12次游戏,求他平均可以得到多少奖励分?
答案
1 |
6 |
1 |
3 |
1 |
2 |
1 |
3 |
1 |
2 |
1 |
6 |
则P(x<2)=P(x=1)=
1 |
6 |
2 |
3 |
P(x<2且y>1)=P(x<2)•P(y>1)=
1 |
9 |
(2)ξ的取值范围为2,3,4,6.
P(ξ=2)=P(x=1)•P(y=1)=
1 |
6 |
1 |
3 |
1 |
18 |
P(ξ=3)=P(x=1)•P(y=2)+P(x=2)•P(y=1)=
1 |
6 |
1 |
2 |
1 |
3 |
1 |
3 |
7 |
36 |
P(ξ=4)=P(x=1)•P(y=3)+P(x=2)•P(y=2)+P(x=3)•P(y=1)=
1 |
6 |
1 |
6 |
1 |
3 |
1 |
2 |
1 |
2 |
1 |
3 |
13 |
36 |
P(ξ=5)=P(x=2)P(y=3)+P(x=3)P(y=2)=
1 |
3 |
1 |
6 |
1 |
2 |
1 |
2 |
11 |
36 |
P(ξ=6)=P(x=3)•P(y=3)=
1 |
2 |
1 |
6 |
1 |
12 |
其分布为: