题目
题型:不详难度:来源:
x2 |
3+k |
y2 |
2-k |
答案
x2 |
3+k |
y2 |
2-k |
∴2-k>3+k>0,解不等式得-3<k<-
1 |
2 |
故k的取值范围是(-3,-
1 |
2 |
故答案为:(-3,-
1 |
2 |
核心考点
举一反三
(1)过点A(-1,-2)且与椭圆
x2 |
6 |
y2 |
9 |
(2)过点P(
3 |
3 |
(Ⅰ)当m=
| ||
2 |
5 |
4 |
(Ⅱ)若OB∥AN,求离心率e的取值范围.
4 |
5 |
π |
3 |
3 |
x2 |
3+k |
y2 |
2-k |
x2 |
3+k |
y2 |
2-k |
1 |
2 |
1 |
2 |
1 |
2 |
x2 |
6 |
y2 |
9 |
3 |
3 |
| ||
2 |
5 |
4 |
4 |
5 |
π |
3 |
3 |