题目
题型:填空题难度:一般来源:不详
g | 25 |
答案
g | 25 |
=5log53-2log31+3log84
=3-0+3×
2lg2 |
3lg2 |
=5
故答案为:5
核心考点
举一反三
1 |
2 |
1 |
3 |
1 |
2 |
1 |
4 |
8 |
125 |
2 |
1 |
25 |
x-3 |
x+3 |
(1)证明:a>3;
(2)问是否存在实数m,使得自变量x在定义域[α,β]上取值时,该函数的值域恰好为[logm(mβ-m),logm(mα-m)],若存在,求出实数m的取值范围,若不存在,请说明理由.
g | 25 |
g | 25 |
2lg2 |
3lg2 |
1 |
2 |
1 |
3 |
1 |
2 |
1 |
4 |
8 |
125 |
2 |
1 |
25 |
x-3 |
x+3 |