题目
题型:不详难度:来源:
A.15° | B.30° | C.60° | D.75° |
答案
∵AB是圆的直径,
∴∠ADB=90°,
∴∠ABD=∠ACD=15°,
∴∠BAD=90°-∠ABD=75°.
故选D.
核心考点
举一反三
AE |
A.30° | B.45° | C.60° | D.90° |
2 |
已知,△ABC是等边三角形且内接于⊙O,取
AB |
(1)如图1,图2,图3,M分别为
AB |
A.15° | B.30° | C.60° | D.75° |
AE |
A.30° | B.45° | C.60° | D.90° |
2 |
AB |
AB |