题目
题型:单选题难度:简单来源:不详
A.1 | B.-1 | C.1或-1 | D.任意数 |
答案
∴a+b=0,∴a=-b.
解方程ax+b=0,
得:x=-
b |
a |
即x=1.
故选A.
核心考点
举一反三
2(x-1) |
3 |
x-3 |
2 |
A.x+4(x-1)=1-3(x-3) | B.x+4(x-1)=6-3(x-3) |
C.6x+2(x-1)=6-3(x-3) | D.6x+4(x-1)=6-3(x-3) |
x |
3 |
(1)-2x+8=x-1;
(2)
2-x |
3 |
3(x-1) |
2 |
A.1 | B.-1 | C.1或-1 | D.任意数 |
b |
a |
2(x-1) |
3 |
x-3 |
2 |
A.x+4(x-1)=1-3(x-3) | B.x+4(x-1)=6-3(x-3) |
C.6x+2(x-1)=6-3(x-3) | D.6x+4(x-1)=6-3(x-3) |
x |
3 |
2-x |
3 |
3(x-1) |
2 |