题目
sin22°30′cos22°30′=______.
提问时间:2021-03-26
答案
sin22°30′cos22°30′
=
×2sin22°30′cos22°30′
=sin(2×22°30′)
=sin45°
=
=
1 |
2 |
=sin(2×22°30′)
=sin45°
=
|