题目
3x的3次方-3x的平方y+8y-8X
提问时间:2021-01-26
答案
3x^3-3xy^2+8y-8x
=3x(x^2-y^2)-8(x-y)
=3xy(x-y)(x+y)-8(x-y)
=(x-y)[3xy(x+y)-8]
=(x-y)(3x^2+3xy^2-8)
=3x(x^2-y^2)-8(x-y)
=3xy(x-y)(x+y)-8(x-y)
=(x-y)[3xy(x+y)-8]
=(x-y)(3x^2+3xy^2-8)
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