题目

用指向函数的指针作函数参数,求分段函数当x＜0时,y＝x＋2;当0≤x＜5时,y＝3x－1;当x≥5时,y＝x(x－1)

提问时间：2021-01-02

答案

double fun1(double x){return x+2;}double fun2(double x){return 3*x-1;}double fun3(double x){return x*(x-1);}void main(){double x;scanf("%lf",&x);double (*fun)(double); //函数指针if(x