题目

计算：(6x^4y-10x^3Y^2+14x^2y^5)/(-2x^2y)
(6x^4y-10x^3Y^2+14x^2y^5)/(-2x^2y)
（2/3a^4b^4-1/9a^2b^3）/(-1/3ab)^2
[3a(2a)^2-(4a)^2+8a^2/(-2a)]/(4a)
(21x^5y^3-6x^4y^3z+3x^3y^4)/(-1/3x^3y^3)

提问时间：2020-11-14

答案

(6x^4y-10x^3Y^2+14x^2y^5)/(-2x^2y)
=(2x^2y)(3x^2-5xY+7y^4)/(-2x^2y)
=-(3x^2-5xY+7y^4)
=-3x^2＋5xY-7y^4
（2/3a^4b^4-1/9a^2b^3）/(-1/3ab)^2
=[1/9(ab)^2]（6a^2b^2-b）/[1/9(ab)^2]
=6a^2b^2-b
[3a(2a)^2-(4a)^2+8a^2/(-2a)]/(4a)
=(3a×4a^2-16a^2-4a)/(4a)
=4a×(3a^2-4a-1)/(4a)
=3a^2-4a-1
(21x^5y^3-6x^4y^3z+3x^3y^4)/(-1/3x^3y^3)
=x^3y^3(21x^2-6xz+3y)/(-1/3x^3y^3)
=(21x^2-6xz+3y)×x^3y^3/(-1/3x^3y^3)
=-(21x^2-6xz+3y)×3
=-63x^2＋18xz-9y