题目
1-(a²+8)/(a²+4a+4)÷(4a-4)/(a²+2a)
提问时间:2020-08-04
答案
1-(a²+8)/(a²+4a+4)÷(4a-4)/(a²+2a)
=[(a²+4a+4-a²-8﹚/﹙a²+4a+4﹚]×[﹙a²+2a﹚/﹙4a-4﹚]
=[(4a-4﹚/﹙a+2﹚²]×[a﹙a+2﹚/﹙4a-4﹚]
=a/(a+2)
=[(a²+4a+4-a²-8﹚/﹙a²+4a+4﹚]×[﹙a²+2a﹚/﹙4a-4﹚]
=[(4a-4﹚/﹙a+2﹚²]×[a﹙a+2﹚/﹙4a-4﹚]
=a/(a+2)
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