题目
题型:不详难度:来源:
OA |
OB |
OC |
A.
| B.
| ||||||||||||||||||||
C.
| D.
|
答案
OA |
OB |
OC |
0 |
∴O为△ABC的重心
∴
OA |
2 |
3 |
1 |
2 |
AB |
AC |
1 |
3 |
AB |
AC |
1 |
3 |
AB |
AB |
BC |
1 |
3 |
AB |
BC |
2 |
3 |
AB |
1 |
3 |
BC |
故选项为D
核心考点
试题【已知A、B、C三点不共线,且点O满足OA+OB+OC=0,则下列结论正确的是( )A.OA=13AB+23BCB.OA=23AB+13BCC.OA=-13AB】;主要考察你对平面向量的加法等知识点的理解。[详细]
举一反三
x |
x |
a |
x |
A.2
| B.-2
| C.
| D.-
|
AB |
CD |
CB |
AD |
A.
| B.
| C.
| D.
|
AB |
a |
AC |
b |
AD |
A.
| B.
| C.
| D.-
|
![](http://img.shitiku.com.cn/uploads/allimg/20191104/20191104001828-25646.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191104/20191104001828-62209.png)