题目
题型:不详难度:来源:
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102231834-13915.png)
A.m<-1或m>2 | B.m<-1 |
C.m>2 | D.m≤-1或m≥2 |
答案
解析
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102231834-13915.png)
由题意利用数轴,易得1+m<0或-1+m>1,即m<-1或m>2.
核心考点
举一反三
题型:x-1|≤m}.
(1)若(P∪S)⊆P,求实数m的取值范围;
(2)是否存在实数m,使得“x∈P”是“x∈S”的充要条件?若存在,求出m的取值范围;若不存在,请说明理由.
(1)若(P∪S)⊆P,求实数m的取值范围;
(2)是否存在实数m,使得“x∈P”是“x∈S”的充要条件?若存在,求出m的取值范围;若不存在,请说明理由.
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102231823-13392.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102231824-43255.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102231824-87768.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102231824-84359.png)
A.充分不必要条件 | B.必要不充分条件 | C.充要条件 | D.非充分非必要条件 |
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102231815-16892.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102231815-13792.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102231815-43545.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102231815-64866.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102231816-49122.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102231815-43545.png)
A.![]() | B.![]() | C.![]() | D.![]() |
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102231810-19032.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102231810-78289.png)
A.充分不必要条件 | B.必要不充分条件 | C.充分必要条件 | D.既不充分也不必要条件 |
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102231757-74013.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102231757-91567.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102231758-47278.png)
A.充分不必要条件 | B.必要不充分条件 |
C.充要条件 | D.既不充分也不必要条件 |