题目
题型:不详难度:来源:
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080320-31184.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080320-30325.png)
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![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080320-57198.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080321-19323.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080321-30102.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080321-81015.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080321-91514.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080320-30325.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080321-81015.png)
答案
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080322-97054.png)
解析
试题分析:利用二次方程的韦达定理求出|x1-x2|,将不等式恒成立转化为求函数的最值,求出命题p为真命题时m的范围;利用二次方程有两个不等根判别式大于0,求出命题Q为真命题时m的范围;P且Q为真转化为两个命题全真,求出m的范围.解:由题设x1+x2=a,x1x2=-2,∴|x1-x2|=
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080322-88080.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080322-88080.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080322-62711.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080322-62711.png)
点评:本题考查二次方程的韦达定理、二次方程有根的判断、复合命题的真假与构成其简单命题的真假的关系.
核心考点
举一反三
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080241-23753.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080224-59773.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080204-53721.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080204-61534.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080204-46207.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080205-96277.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080205-88019.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080147-23145.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080147-62426.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080147-96993.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080148-17246.png)
则在命题
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080148-89568.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080148-88001.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080148-53856.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080149-86364.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080149-80045.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080149-72350.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080149-88804.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080150-34174.png)
A.![]() ![]() | B.![]() ![]() | C.![]() ![]() | D.![]() ![]() |
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080133-17515.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191102/20191102080134-94018.png)
①CF∥DE;②BD∥平面CEF;③AF⊥平面BCE;
④平面CEF⊥平面ADE.
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