题目
题型:不详难度:来源:
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011344-16533.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011344-32560.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011345-82980.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011345-83155.png)
A.![]() | B.![]() | C.![]() | D.![]() |
答案
解析
因为连接B1C,AC,由正方体的几何特征,可得AB1∥B1C,则∠AB1C即为直线AB1与DA1所成角,∵长方体ABCD-A1B1C1D1的高为4,底面ABCD是边长为2的正方形,,则AB1=B1C=2
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011346-32418.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011346-31204.png)
解决该试题的关键是能理解通过平移法,作出异面直线所成的角,然后在三角形中求解。
核心考点
举一反三
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011339-30335.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011333-86080.png)
(1)证明:∠PBC=90°;
(2)若PB=3,求直线AB与平面PBC所成角的正弦值.
如图,四棱锥
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011320-13639.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011320-77566.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011320-42496.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011320-11456.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011321-14967.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011321-30070.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011321-70731.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011321-81424.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011321-35716.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011322-42168.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011322-38409.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011322-57521.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011322-66009.png)
(1)求
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011323-70369.png)
(2)求直线
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011323-95895.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011323-27902.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011311-12157.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011311-55701.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011311-97280.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011312-61442.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011312-98234.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011312-57545.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011311-55701.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011312-68333.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011312-90785.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011312-68333.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011312-61442.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011313-26810.jpg)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011302-24821.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011302-51163.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011302-19343.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011302-97683.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011302-44123.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011303-84017.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011303-77563.jpg)
(Ⅰ)求异面直线
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011303-40872.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011303-86977.png)
(Ⅱ)BE和平面
![](http://img.shitiku.com.cn/uploads/allimg/20191022/20191022011303-82302.png)
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