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题目
题型:闵行区一模难度:来源:
已知复数z满足(1+i)z=4i(i为虚数单位),则z=______.
答案
由(1+i)z=4i,得:z=
4i
1+i
=
4i(1-i)
(1+i)(1-i)
=
4+4i
2
=2+2i

故答案为2+2i.
核心考点
试题【已知复数z满足(1+i)z=4i(i为虚数单位),则z=______.】;主要考察你对复数的代数表示法及其几何意义等知识点的理解。[详细]
举一反三
x的二次方程x2+z1x+z2+m=0中,z1,z2,m均是复数,且z12-4z2=16+20i,设这个方程的两个根α、β,满足|α-β|=2


7
,求|m|的最大值和最小值.
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已知实数m满足2x2-(2i-1)x+m-i=0,求m及x的值.
题型:不详难度:| 查看答案
已知复数z=1+i,求实数a,b使az+2b
.
z
=(a+2z)2
题型:广东难度:| 查看答案
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A.3B.C.-3D.-
已知i是虚数单位,a和b都是实数,且a(1+i)=12+bi,则data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAE0AAAAkCAYAAADM8rciAAABGklEQVRoge2ZSw7DIAwFc4wuA/e/V4/RbBoJIWxswOEFPBJSMAFPKdBPjsNxHMdxRhNj/OX1PCbpp81ZykPFqXzc/aZIBa3y3XUqfl9z7aW6KW+YtJZ6t2T+TqWxvJTaa+P1uJWuJXVpW5cUNbgkZrEaR60ks13RcsBq79H6aHM+eoxwW0AaGyksXTHTDv7WRNaTRp2ZmnOUG6eblsGlHwRTviONAFUa1QtX7A+kH6RUApwfnBABlCeUDAOUJyUTQvjOKhrPKVAy53l+ZhWN5xSgZBigPKFkGOA84YQyIP0gpRJg/UaLaX6f9rQvx3YveATbT5rmGQHVXhtvKRD/hHwN2tWx/aTVnhHU+lD9lp00356N+DMCx3mCC4iHUwquueUVAAAAAElFTkSuQmCC等于(  )
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