题目
题型:填空题难度:一般来源:不详
2 |
八 |
2 |
1 |
4 |
答案
2 |
多 |
2 |
1 |
4 |
=1+
2 |
|
=2-2(lg5+lg2)
=2-2
=0
故答案为:0.
核心考点
举一反三
x-1 |
x+1 |
(1)求f(x)的定义域;
(2)判断g(x)的奇偶性;
(3)画出函数y=f(x)的图象,并写出图象的对称中心.
(1)试比较f(m-1)+f(m+1)与2f(m)的大小;
(2)求△ABC的面积S=g(m)的值域.
1 |
2 |
1 |
2 |
1 |
2 |
A.0<x1x2<1 | B.x1x2=1 | C.1<x1x2<2 | D.x1x2≥2 |
题型:(a>0,a≠1),若x1<x2<x3<x4,且f(x1)=f(x2)=f(x3)=f(x4),则
+
+
+
=( )
1 |
x1 |
1 |
x2 |
1 |
x3 |
1 |
x4 |
A.2 | B.4 | C.8 | D.随a值变化 |
A.①② | B.②③ | C.①③ | D.③④ |