题目

求以下几道题的脱式简便算法!
1.125X25x3232x69
2.2006÷2007/2008
3.201x17/25
4.112又23分之14÷37
5.10101/131313x91
6.567÷567又568分之567
7.231÷231又232分之231

提问时间：2021-05-07

答案

1.125X25x3232x69
=(125X8)X(25X4)x(101x69)
=1000X100X(100+1)X69
=100000X100X69+100000X1X69
=690000000+6900000
=696900000
2.2006÷2007/2008
=2006X2008/2007
=2006X(1+1/2007)
=2006X1+2006X1/2007
=2006+2006/2007
=2006又2006/2007
3.201x17/25
=(200+1)X17/25
=200X17/25+1X17/25
=136+17/25
=136又17/25
4.112又23分之14÷37
=（111+1又14/23）X1/37
=111X1/37+37/23X1/37
=3+1/23
=3又1/23
5.10101/131313x91
=10101/（13X10101）X91
=1/13X91
=7
6.567÷567又568分之567
=[(567×568)/568]÷[(567×567)/568]
=[（567×568）/568]×[568/(567×567)/]
=568/567
=1又1/567
7.231÷231又232分之231
=[(231×232)/232]÷[(231×231)/232]
=[（231×232）/232]×[232/(231×231)]
=232/231
=1又1/231