题目

已知sin[(π/4)-x)]=5/13,0<x<π/4.求cos2x/(cosπ/4+
已知sin[(π/4)-x)]=5/13,0<x<π/4.求cos2x/[cos(π/4)+x] 已知0<β<π/2<α<π,cos[α-(β/2)]=-1/9,sin[(α/2)-β]=2/3 求cos(α+β) 已知α,β∈(0,π)且tan(α-β)=1/2,tanβ=-1/7.求2α-β

提问时间：2021-04-27

答案

1.∵sin[(π/4)-x)]=5/13,0<x<π/4 ∴cos[(π/4)-x)]=12/13 cos2x=cos[(π/2)-2x]=2sin[(π/4)-x)]*cos[(π/4)-x)]=2×5/13×12/13=120/169 cos[(π/4)+x]=sin[π/2-(π/4+x)]=sin(π/4-x)=5/13 ∴cos2x/cos...