题目
(x+2y)^2(x-2y)^2-2(x+2y)(x-2y),其中x=2008,y=-1
提问时间：2021-04-08
答案
(x+2y)^2(x-2y)^2-2(x+2y)(x-2y)
=(x+2y)^2(x-2y)^2-2(x+2y)(x-2y)+1-1
=[(x+2y)(x-2y)-1]^2+1
=(2006×2010-1)^2+1
=16257499779482
=(x+2y)^2(x-2y)^2-2(x+2y)(x-2y)+1-1
=[(x+2y)(x-2y)-1]^2+1
=(2006×2010-1)^2+1
=16257499779482
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