题目
x-y+(y2/x+y)+(x2/x-y)
提问时间：2021-04-01
答案
x-y+(y²/x+y)+(x²/x-y)
=x(x²-y²)/(x²-y²)-y(x²-y²)/(x²-y²)+y²(x-y)/(x²-y²)+x²(x+y)/(x²-y²)
=(x³-xy²-x²y+y³+xy²-y³+x³+x²y)/(x²-y²)
=2x³/(x²-y²)
=x(x²-y²)/(x²-y²)-y(x²-y²)/(x²-y²)+y²(x-y)/(x²-y²)+x²(x+y)/(x²-y²)
=(x³-xy²-x²y+y³+xy²-y³+x³+x²y)/(x²-y²)
=2x³/(x²-y²)
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