题目

sin(a+b)sin(a-b)怎么化成 负二分之一（cos2a-cos2b)

提问时间：2021-04-01

答案

cos2a=cos[(a+b)+(a-b)]=cos(a+b)cos(a-b)-sin(a+b)sin(a-b)
cos2b=cos[(a+b)-(a-b)]=cos(a+b)cos(a-b)+sin(a+b)sin(a-b)
cos2a-cos2b=cos(a+b)cos(a-b)-sin(a+b)sin(a-b)-(cos(a+b)cos(a-b)+sin(a+b)sin(a-b))
=-2sin(a+b)sin(a-b)
所以
sin(a+b)sin(a-b)=-1/2(cos2a-cos2b)