题目
求值:sin21°cos81°-sin69°cos9°=______.
提问时间:2021-03-31
答案
sin21°cos81°-sin69°cos9°=sin21°cos(90°-9°)-sin(90°-21°)cos9°
=sin21°sin9°-cos21°cos9°=-(cos21°cos9°-sin21°sin9°)=-cos(21°+9°)=-cos30°=-
=sin21°sin9°-cos21°cos9°=-(cos21°cos9°-sin21°sin9°)=-cos(21°+9°)=-cos30°=-
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