题目

已知函数y=f(x)是偶函数,y=f(x-2)在【0,2】上单调递减则：A f(0)提问时间：2021-03-17

答案

0<=x<=2,
-2<=x-2<=0.
f(x)在[-2,0]上单调递减. f(-1)>=f(0), 所以,B不对.
f(x)在[0,2]上单调递增. f(0)<=f(1)<=f(2). f(0)<=f(1)=f(-1)<=f(2). A对.