题目
已知x2-8x+y2-y+16
1 |
4 |
提问时间:2021-03-17
答案
x2-8x+y2-y+16
=0,
(x-4)2+(y-
)2=0,
x-4=0,y-
=0,
x=4,y=
,
[(x+y)(x-y)-(x+y)2-2y(x-3y)]÷4y
=[x2-y2-x2-y2-2xy-2xy+6y2]÷4y
=[4y2-4xy]÷4y
=y-x
=
-4
=-3
.
1 |
4 |
(x-4)2+(y-
1 |
2 |
x-4=0,y-
1 |
2 |
x=4,y=
1 |
2 |
[(x+y)(x-y)-(x+y)2-2y(x-3y)]÷4y
=[x2-y2-x2-y2-2xy-2xy+6y2]÷4y
=[4y2-4xy]÷4y
=y-x
=
1 |
2 |
=-3
1 |
2 |
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