题目

数学一元二次方程 明天就要交
①9√1/46÷2/3√3/5×1/2√2又2/3
②10a²√ab×5√a分之b ÷ 15√a分之b

提问时间：2021-03-15

答案

①原式=9√(1/46)÷2/3√(3/5)×1/2√(2又2/3)
=(9÷2/3×1/2)×√(1/46÷3/5×2又2/3)
=(9×3/2×1/2)×√(1/46×5/3×8/3)
=27/4×√(20×1/9×1/23)
=27/4×√[2²×5×(1/3)²×23/23²]
=(27/4)×2×1/3×1/23×√(5×23)
=9/46×√115
=(9√115)/46
②原式=10a²√(ab)×5√(b/a)÷15√(b/a)
=(10a²×5÷15)×√(ab×b/a÷b/a)
=(10a²/3)×√(ab)
=10a²√(ab)/3