题目

紧急~~~分解因式：①(x^4)-(3x^3)-(5x^2)+3x+4=? ②(x^3)-(6x^2)+9x-4=? ③(x^3)+(12x^2)+47x+60=?求大神
要有过程

提问时间：2021-01-05

答案

这么简单的题目居然到现在米仁回答 ①原式=x^4-3^3-4x^3-x^2+3x+4 =(x^4-3^3-4x^3)-(x^2-3x-4) =x^2(x^2-3x-4)-(x^2-3x-4) =(x^2-3x-4)(x^2-1) =(x-4)(x+1)(x-1)(x+1) =(x-1)(x-4)(x+1)^2 ②原式=x^3-x^2-5x^2+9x-4 =x^2(x-1)-(5x^2-9+4) =x^2(x-1)-(x-1)(5x-4) =(x-1)[x^2-(5-4)] =(x-1)(x^2-5+4) =(x-1)(x-1)(x-4) =(x-4)(x-1)^2 ③原式=(x^3+3x^2)+(9x^2+47x+60) =x^2(x+3)+(x+3)(9x+20) =(x+3)(x^2+9x+20) =(x+3)(x+4)(x+5) 过程够详细了吧