题目
X^2-3X-2=0,求( x - 2x-1/x )÷(x-1)/(x^2-2x)
提问时间：2020-12-17
答案
( x - 2x-1/x )÷(x-1)/(x^2-2x)
=(x²-2x+1)/x ×x(x-2)/(x-1)
=(x-1)²/x ×x/(x-2)/(x-1)
=(x-1)(x-2)
=x²-3x+2
=x²-3x-2 +4
∵x²-3x-2=0
∴原式=0+4
=4
=(x²-2x+1)/x ×x(x-2)/(x-1)
=(x-1)²/x ×x/(x-2)/(x-1)
=(x-1)(x-2)
=x²-3x+2
=x²-3x-2 +4
∵x²-3x-2=0
∴原式=0+4
=4
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