题目

已知函数f(x)=sin(x＋π/6)＋2sin∧2 x/2,求f(x)最大值

提问时间：2020-12-13

答案

f(x)=sin(x＋π/6)＋2sin∧2 x/2
=sin(x＋π/6)＋1-cosx
=sinxcos(π/6)+cosxsin(π/6)+1-2cosxsin(π/6)
=sinxcos(π/6)-cosxsin(π/6)+1
=sin(x-π/6)+1
-2≤f(x)≤2
f(x)最大值是2