题目

解不等式2loga(x-1)≥loga(ax+1)(a＞1)

提问时间：2020-11-16

答案

2log(x-1)≥log(ax+1)log(x-1)^2≥log(ax+1)x≠1 and ax+1 >0 and (x-1)^2 ≥ ax+1x≠1 and x> 1/a and x^2 - (2+a)x ≥0x≠1 and x> 1/a and "x≤0 or x≥ 1/(2+a)"ie x>1/a