题目

输入n个整数,求输入正数之和,负数之和,并统计相应正数和负数的个数,以输入0表示输入结束.

提问时间：2020-11-13

答案

C版本：
#include
int main(){
int numPos = 0,sumPos = 0,numNeg = 0,sumNeg = 0,in;
printf("Please key in the integers,key in 0 to stop: ");
do{
scanf("%d",&in);
if(in > 0){
numPos++;
sumPos += in;
}
else if(in < 0){
numNeg++;
sumNeg += in;
}
}while(in != 0);
printf("There are %d positive integers,whose sum is %d. ",numPos,sumPos);
printf("There are %d negative integers,whose sum is %d. ",numNeg,sumNeg);
return 0;
}
borland C版本5.5编译通过.
Java版本：
import java.util.Scanner;
public class test{
public static void main(String[] args){
Scanner sc = new Scanner(System.in);
int numPos = 0,sumPos = 0,numNeg = 0,sumNeg = 0,in;
System.out.println("Please key in the integers,0 to stop");
do{
in = sc.nextInt();
if(in > 0){
numPos++;
sumPos += in;
}
else if(in < 0){
numNeg++;
sumNeg += in;
}
}while(in != 0);
System.out.println("There are " + numPos + " positive integers,whose sum is " + sumPos);
System.out.println("There are " + numNeg + " negative integers,whose sum is " + sumNeg);
}
}
JGrasp 版本1.8.6_10编译通过.