题目
(1-2)^2 / X-1
— —
X+1 X+1
..
就是 (1- X+1分之2)的平方除以X+1分之X-1
— —
X+1 X+1
..
就是 (1- X+1分之2)的平方除以X+1分之X-1
提问时间:2020-10-31
答案
[1-2/(x+1)]^2÷(x-1)/(x+1)
=[1-2/(x+1)]^2*(x+1)/(x-1)
=[(x+1-2)/(x+1)]^2*(x+1)/(x-1)
=[(x-1)/(x+1)]^2*(x+1)/(x-1)
=(x-1)^2/(x+1)^2*(x+1)/(x-1)
=(x-1)/(x+1)
=[1-2/(x+1)]^2*(x+1)/(x-1)
=[(x+1-2)/(x+1)]^2*(x+1)/(x-1)
=[(x-1)/(x+1)]^2*(x+1)/(x-1)
=(x-1)^2/(x+1)^2*(x+1)/(x-1)
=(x-1)/(x+1)
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