题目

求与双曲线9分之x2-16分之y2=1有共同渐近线且经过点M（-3 4根号3）的双曲线标准方程.

提问时间：2020-10-22

答案

一条渐近线方程为 y=(3/4)x设双曲线 a=3m,则焦点在x轴,b=4m；a=4n,则焦点在y轴,b=3nx^2/9m^2-y^2/16m^2=1 => 9/9m^2-48/16m^2=1 => -2=m^2 => m无解y^2/16n^2-x^2/9n^2=1 => 48/16n^2-9/9n^2=1 =...