当前位置: > 计算:1/(x+1) * [(x-3)/(x^2 + 6x + 9) + 2/(3+x)] - x/(x^2 - 9)...
题目
计算:1/(x+1) * [(x-3)/(x^2 + 6x + 9) + 2/(3+x)] - x/(x^2 - 9)

提问时间:2020-10-13

答案
1/(x+1) * [(x-3)/(x^2 + 6x + 9) + 2/(3+x)] - x/(x^2 - 9)
=1/(x+1)[(x-3)/(x+3)^2+2(x+3)/(3+x)^2] - x/(x+3)(x-3)
=(x-3+2x+6)/[(x+1)(x+3)^2]-x/(x+3)(x-3)
=3(x+1)/[(x+1)(x+3)^2]-x/(x+3)(x-3)
=3/(x+3)^2-x/(x+3)(x-3)
=3(x-3)/(x+3)^2(x-3)-x(x+3)/(x+3)^2(x-3)
=(3x-9-x^2-3x)/(x+3)^2(x-3)
=(3x-9-x^2-3x)/(x+3)^2(x-3)
=-(x^2+9)/(x+3)^2(x-3)
举一反三
我想写一篇关于奥巴马的演讲的文章,写哪一篇好呢?为什么好
奥巴马演讲不用看稿子.为什么中国领导演讲要看?
想找英语初三上学期的首字母填空练习……
英语翻译
1,人们染上烟瘾,最终因吸烟使自己丧命.
版权所有 CopyRight © 2012-2019 超级试练试题库 All Rights Reserved.