题目
设函数f(x)=cos(x+
2 |
3 |
提问时间:2020-10-13
答案
(I)f(x)=cos(x+
π)+2cos2
=cosxcos
π-sinxsin
π+cosx+1
=-
cosx-
2 |
3 |
x |
2 |
=cosxcos
2 |
3 |
2 |
3 |
=-
1 |
2 |
|