题目
因式分解 (a²-b²-1/2b-1/16) (x²-6x-2)(x²-6x+4)-7
提问时间:2020-10-13
答案
(a²-b²-1/2b-1/16)
=a²-(b+1/4)²
=(a+b+1/4)(a-b-1/4)
(x²-6x-2)(x²-6x+4)-7
=(x²-6x-2)²+6(x²-6x-2)-7
=(x²-6x-2+7)(x²-6x-2-1)
=(x²-6x+5)(x²-6x-3)
=(x-1)(x-5)(x²-6x-3)
=a²-(b+1/4)²
=(a+b+1/4)(a-b-1/4)
(x²-6x-2)(x²-6x+4)-7
=(x²-6x-2)²+6(x²-6x-2)-7
=(x²-6x-2+7)(x²-6x-2-1)
=(x²-6x+5)(x²-6x-3)
=(x-1)(x-5)(x²-6x-3)
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