题目
多项式2a2b-ab2与-
1 |
2 |
提问时间:2020-10-11
答案
根据题意得:(2a2b-ab2)-(-
ab2+a2b)
=2a2b-ab2+
ab2-a2b
=a2b-
ab2,
故答案为:a2b-
ab2.
1 |
2 |
=2a2b-ab2+
1 |
2 |
=a2b-
1 |
2 |
故答案为:a2b-
1 |
2 |
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