题目
小学六年级上册简算题,要答案
提问时间:2020-10-04
答案
2002乘20032003-2003乘20022002
=2002x20032003-(2002+1)20022002
=2002x20032003-2002x20022002-20022002
=2002(20032003-20022002)-20022002
=2002x10001-20022002
=2002x1001-2002x1001
=0
2+4+6+8+···+2004
=1005006
当n==1002时,
s=1002×(1002+1)=1005006.
即2+4+6+8+…+2004=1005006.
0.888乘125乘73+999乘3
125(0.8+0.08+0.008)x73+999x3
=(100+10+1)x73+111x9x3
=111x73+111x27
=111x100
=111001.6÷ 3/8 – 3/8 ÷6
=1/6x(3/8-3/8)
=1/6x0
=0
2.4/7 × 5/9 + 3/7 × 5/9
=(4/7+3/7)x5/9
=1x5/9
=5/9
3.5/2 -( 3/2 + 4/5 )
=5/2-3/2-4/5
=1-4/5
=1/5
4.6 ×( 1/2 + 2/3 )
=6x1/2+6x2/3
=3+4
=7
5.8 × 4/5 + 8 × 11/5
=8x(4/5+11/5)
=8x3
=24
6.31 × 5/6 – 5/6
=(31-1)x5/6
=30x5/6
=25
7.4/5 × 25/16 + 2/3 × 3/4
=5/4+1/2
=5/4+2/4
=7/4
8.101 × 1/5 – 1/5 × 21
=(101-21)x1/5
=80x1/5
=16
=2002x20032003-(2002+1)20022002
=2002x20032003-2002x20022002-20022002
=2002(20032003-20022002)-20022002
=2002x10001-20022002
=2002x1001-2002x1001
=0
2+4+6+8+···+2004
=1005006
当n==1002时,
s=1002×(1002+1)=1005006.
即2+4+6+8+…+2004=1005006.
0.888乘125乘73+999乘3
125(0.8+0.08+0.008)x73+999x3
=(100+10+1)x73+111x9x3
=111x73+111x27
=111x100
=111001.6÷ 3/8 – 3/8 ÷6
=1/6x(3/8-3/8)
=1/6x0
=0
2.4/7 × 5/9 + 3/7 × 5/9
=(4/7+3/7)x5/9
=1x5/9
=5/9
3.5/2 -( 3/2 + 4/5 )
=5/2-3/2-4/5
=1-4/5
=1/5
4.6 ×( 1/2 + 2/3 )
=6x1/2+6x2/3
=3+4
=7
5.8 × 4/5 + 8 × 11/5
=8x(4/5+11/5)
=8x3
=24
6.31 × 5/6 – 5/6
=(31-1)x5/6
=30x5/6
=25
7.4/5 × 25/16 + 2/3 × 3/4
=5/4+1/2
=5/4+2/4
=7/4
8.101 × 1/5 – 1/5 × 21
=(101-21)x1/5
=80x1/5
=16
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