题目
化学 写出NH4CL,Na3PO4的离子浓度顺序,电荷守恒,物料守恒,质子守恒.
提问时间：2020-09-30
答案
NH4Cl
离子浓度顺序,cCl-大于cNH4+大于cH+大于cOH-
电荷守恒,cCI-+cOH-=cNH4+ +cH+
物料守恒,cNH4+ +cNH3.H2O=cCl-
质子守恒,cH+=cNH3.H2O+cOH-
Na3PO4离子浓度顺序
cNa+大于cPO43-大于cOH-大于cHPO42-大于cH2PO4-
电离守恒,cNa+ +cH+=3cPO43-+2cHPO42-+cH2PO4-+cOH-
物料守恒,cNa+=3cPO43-+3cHPO42-+3cH2PO4-+3cH3PO4
质子守恒,cOH-=cH+ +cH2PO4-+2cHPO42-+3cH3PO4
离子浓度顺序,cCl-大于cNH4+大于cH+大于cOH-
电荷守恒,cCI-+cOH-=cNH4+ +cH+
物料守恒,cNH4+ +cNH3.H2O=cCl-
质子守恒,cH+=cNH3.H2O+cOH-
Na3PO4离子浓度顺序
cNa+大于cPO43-大于cOH-大于cHPO42-大于cH2PO4-
电离守恒,cNa+ +cH+=3cPO43-+2cHPO42-+cH2PO4-+cOH-
物料守恒,cNa+=3cPO43-+3cHPO42-+3cH2PO4-+3cH3PO4
质子守恒,cOH-=cH+ +cH2PO4-+2cHPO42-+3cH3PO4
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