题目
-17π/3求他的三角函数值?
说明方法
说明方法
提问时间：2020-09-03
答案
sin(-17π/3)
=-sin(17π/3)
=-sin(4π+π+2π/3)
=-sin(π+2π/3)
=-[-sin(2π/3)]
=sin(2π/3)=√3/2;
cos（-17π/3)
=cos(17π/3)
=cos(5π+2π/3)
=cos(4π+π+2π/3)
=cos(π+2π/3)
=-cos(2π/3)
=-1/2.
=-sin(17π/3)
=-sin(4π+π+2π/3)
=-sin(π+2π/3)
=-[-sin(2π/3)]
=sin(2π/3)=√3/2;
cos（-17π/3)
=cos(17π/3)
=cos(5π+2π/3)
=cos(4π+π+2π/3)
=cos(π+2π/3)
=-cos(2π/3)
=-1/2.
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