题目
因式分解(x²-y)²-(1-y)²
提问时间:2020-08-07
答案
(x²-y)²-(1-y)²
=[(x²-y+(1-y)][(x²-y-(1-y)]
=(x²-y+1-y)(x²-y-1+y)
=(x²-2y+1)(x²-1)
=(x²-2y+1)(x+1)(x-1)
=[(x²-y+(1-y)][(x²-y-(1-y)]
=(x²-y+1-y)(x²-y-1+y)
=(x²-2y+1)(x²-1)
=(x²-2y+1)(x+1)(x-1)
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