题目
已知函数f（x）=sin2（x-
| π |
| 6 |
提问时间：2020-08-07
答案
（1）由题意得，
f（x）=(sinxcos
−cosxsin
)2+(cosxcos
+sinxsin
)2+sinx•cosx
=sin2x+sinx•cosx+
=
(sin2x−cos2x)+1
=
f（x）=(sinxcos
| π |
| 6 |
| π |
| 6 |
| π |
| 3 |
| π |
| 3 |
=sin2x+sinx•cosx+
| 1 |
| 2 |
| 1 |
| 2 |
=
|