题目

解下列方程【题目见问题补充】【要有步骤】[20道初中方程求帮助]
A.5（X-5)+2=-4 B.3（X-2)=(8-8X) C.3X-12+4(X-3)=2(X+1)-5 D.3X-2(X+2)=4(X-1)+7 E.3X-2[X-5(X+1)-4]=4 F.4/3[3/4(1/5X-2)-6]=1 G.3(X+5)+5[(X+5）-1]=7(X+5)-1 H.5(2-3X)=4(X+1) I.3-2（X-1)=2(X-3) J.1/3(6X-3)-1/2(8X-4)=5 k.(3X+2)+2[(X-1)-(2X+1)]=6 L.3X-2/5=X+1/2 M.4(X+2)/3-X-7/5=12 N.t-t-1/2=2-t+2/3 O.3x-2(x+3)/3=6-x-2/6 P.3/2[2/3(X/4-1)-2]-8=X Q.2X+1/3-5X-1/6=1 R.3(2X+1)/4-2(2X-1)/3=1 S.y-y-1/2=2-y+2/5

提问时间：2020-08-01

答案

a:
5(x-5)+2=-4
5x-25+2=-4
5x=19
x=19/5
b:
3（X-2)=(8-8X)
3x-6=8-8x
11x=14
x=14/11
c:
3X-12+4(X-3)=2(X+1)-5
3x-12+4x-12=2x+2-5
7x-24=2x-3
5x=21
x=21/5
d:
3X-2(X+2)=4(X-1)+7
3x-2x-4=4x-4+7
x-4=4x+3
-3x=7
x=-7/3
e:
3X-2[X-5(X+1)-4]=4
3x-2[x-5x-5-4]=4
3x-2[-4x-9]=4
3x+8x+18=4
11x=-14
x=-14/11
f:
4/3[3/4(1/5X-2)-6]=1
(1/5x-2)-8=1
1/5x=11
x=55
g:
3(X+5)+5[(X+5）-1]=7(X+5)-1
3(x+5)+5(x+5)-5=7(x-5)-1
8(x-5)-7(x-5)=4
x-5=4
x=9
h:
5(2-3X)=4(X+1)
10-15x=4x+4
-19x=-6
x=6/19
i:
3-2（X-1)=2(X-3)
3-2x+2=2x-6
-4x=-11
x=11/4
j:
1/3(6X-3)-1/2(8X-4)=5
2x-1-4x+2=5
-2x=4
x=-2
k:
(3X+2)+2[(X-1)-(2X+1)]=6
3x+2+2(x-1)-2(2x+1)=6
3x+2+2x-2-4x-2=6
x=8
l:
3X-2/5=X+1/2
3x-x=1/2+2/5
2x=5/10+4/10
2x=9/10
x=9/20
m:
4(X+2)/3-X-7/5=12
(4x+8)/3-x-7/5=12
4x/3+8/3-x-7/5=12
x/3=12+7/5-8/3
x=36+21/5-8
x=28+21/5=161/5
n:
t-t-1/2=2-t+2/3
-1/2=2-t+2/3
t=8/3+1/2
t=16/6+3/6
t=19/6
o:
3x-2(x+3)/3=6-x-2/6
3x-2x/3-2=6-x-1/3
7x/3-2=-x+6-1/3
10x/3=8-1/3
10x=25
x=5/2
p:
3/2[2/3(X/4-1)-2]-8=X
2/3[x/6-2/3-2]-8=x
x/9-4/9-4/3-8=x
x-4-12-72=9x
-8x=88
x=-11
q:
2X+1/3-5X-1/6=1
12x+2-30x-1=6
-18x=5
x=-5/18
r:
3(2X+1)/4-2(2X-1)/3=1
9(2x+1)-8(2x-1)=12
18x+9-16x+8=12
2x=-5
x=-5/2
s:
y-y-1/2=2-y+2/5
-1/2=2-y+2/5
y=2+2/5+1/2
y=20/10+4/10+5/10
y=29/10